Question

of the three numbers the first is twice the second and the second is 3 times the third. of their average is 100, the largest of the three numbers is

Answer 1

the largest of three numbers is 360

Answer 2

Let the 2nd no. be x

The 3rd no. be y

The 2nd no. is 3y

So, the 1st no. is 2x or 2(3y)

=6y

Average = 100

=> 6y + 3y + y whole divided by 3 = 100

=> 10y = 100

=> y = 100/10

=> y = 10

1st no. = 2(3y)

= 2(3*10)

= 60

2nd no. = 3y

= 3*10

= 30

3rd no. = y

= 10

Hope this helps...!!!