of the three numbers the first is twice the second and the second is 3 times the third. of their average is 100, the largest of the three numbers is
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the largest of three numbers is 360
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Let the 2nd no. be x
The 3rd no. be y
The 2nd no. is 3y
So, the 1st no. is 2x or 2(3y)
=6y
Average = 100
=> 6y + 3y + y whole divided by 3 = 100
=> 10y = 100
=> y = 100/10
=> y = 10
1st no. = 2(3y)
= 2(3*10)
= 60
2nd no. = 3y
= 3*10
= 30
3rd no. = y
= 10
Hope this helps...!!!
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