Question

Of the three numbers whose average is 60, the first is one fourth of the sum of the others. The first number is:

Answer 1

Let no. be a,b & c
then,

$\frac{a + b + c}{3} = 60 \\ a + b + c = 180.........(1)$

According to question,

$a = \frac{1}{4} (b + c) \\ 4a =( b + c)......(2)$

Putting the Value of (b+c) from (2) in equation (1).

$a + b + c = 180 \\ a + 4a = 180 \\ 5a = 180 \\ a = 36$

Value of First no. is 36.

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