Question

of the
triangle
(b) ABCD is a quadrilateral in which B is 10º more than A. Also D is double of B, and C is
double of A Find the four angles of the quadrilateral.​

Answer 1

Step-by-step explanation:

Let A be x°

So, B=10+x

D=2(10+x)=20+2x

C = 2x

Sum of angles of a quadrilateral is 360°

Therefore, x+(10+x)+(20+2x)+2x=360

=>6x+30=360

=>6x=360-30

=>x=330/6=55

A = 55°

B = 10+55= 65°

C = 2*55 = 110°

D = 20+2*55= 20+110= 130°