Math, asked by abidachehin13, 11 months ago

.Of the two-digit numbers (those from 11 to 95, both inclusive) how many have a second digit greater than the first digit?

Answers

Answered by sujayraj24
0

Answer:

8+7+6+5+4+3+2+1=36

Here is your answer

Answered by anuham97
0

Answer:

36

Step-by-step explanation:

By second digit and first digit, I’ll interpret the second digit as the digit farthest away from the left. (the units digit.) Similarly, I’ll let the first digit be the tens.

from 11 - 20 , there are (12, 13, 14 …, 19 ) 8 numbers.

from 21 - 30, (23, 24 … , 29 ) 7 numbers.

from 31 - 40, 6 numbers.

from 41 - 50, 5 numbers.

from 51 - 60, 4 numbers.

from 61 - 70, 3 numbers.

from 71 - 80, 2 numbers.

from 81 - 90, 1 number. (89)

from 91 - 95, no numbers.

Thus, the total is 8 + 7 + 6 + 5 + 4 + 3 + 2 +1 which is 36.

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