of the waterfalls from a dam into a turbine wheel 19.6m below ,then the velocity of the water at the turbine is(g=9.8m/s)
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hey,
equating kinetic energy = potential energy
1/2 mv^2 = mgh
v = √2gh
putting the values, you will get
v = 19.6 m/s
Hope it helps!
equating kinetic energy = potential energy
1/2 mv^2 = mgh
v = √2gh
putting the values, you will get
v = 19.6 m/s
Hope it helps!
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