Question

of three numbers the product of 1st and 2nd is 24 the product of 2nd and 3rd is 48 and the product of 1st and 3rd is 32 find the three numbers

Answer 1

Answer:

let the three numbers are x,y,z

here, x.y=24

y.z=48

z.x=32

multiplying,

x^2y^2z^2=24.48.32

=24.24.2.32

=24.24.8.8

xyz=24.8

xy=24

z=8

xyz=24.8

yz=48

x=24.8/48=4

xyz=24.8

zx=32

y=24.8/32=6

so the numbers are 4,6,8