Question

Of three numbers, the third is twice the second and the second is 4 times the first. If their average is 78, the smallest of the three numbers is?

Answer 1

I hope you will be able to understand

Answer 2

The smallest of the three numbers is 18.

Step-by-step explanation:

Given,

Average of three numbers = 78

We have to find the smallest of the three numbers.

Let the first number be x and the second number be 4x and the third number be 8x.

∴ Average = $\frac{Sumof allnumbers}{total numbers}$

⇒ $78 = \frac{x + 4x + 8x}{3}$

⇒ $78 \times 3 = x + 4x + 8x$

⇒ $234 = 13x$

⇒ $x = \frac{234}{13}$

⇒ $x = 18$

So, the first number is 18 and the second number is $4 \times 18 = 72$ and the third number is $8\times 18 = 144$.

Hence, the smallest of the three numbers is 18.

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