of three numbers whose average is 60. the first is 1/4th of the sum of the others. what is first number?
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1
Answer:
36
Step-by-step explanation:
Let the three numbers be a,b and c
Given:
- (a + b + c)/3 = 60
- a = 1/4(b + c)
Solution:
a + b + c = 60×3
a + b + c = 180
b + c = 180 - a
b + c = 180 - 1/4(b + c)
b + c + (b + c)/4 = 180
(4b + 4c + b + c)/4 = 180
5b + 5c = 720
5(b + c) = 720
b + c = 720/5
b + c = 144 --->(1)
a = 1/4(b + c) (Given)
a = 1/4(144). ( from (1))
a = 36
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