Question

Of three numbers whose average is 60 the first is one fourthof the sum of others find the first number

Answer 1

Step-by-step explanation:

Let the no be x , y , z

Given ,

Avg of three no = 60

I.e ( x+y+z )/3 = 60

Also , x = (y+z)/4

4x = y +z

Put these in 1st eqn

X +4x = 60*3

5x = 180

X = 36