Question

of three positive numbers;the product of, first and second is 24; second and third is 48 ;and that of first and third is is 32 ;lets find the three numbers numbers.
wrote in steps.
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Answer 1

Step-by-step explanation:

Let the numbers be x,y and z

so..

x*y=24

y*z=48

x*z=32

So x will be...

x=(24/y)

now

(24/y)*z=32

as yz=48,

so z will be..

z=(48/y)

(24/y)(48/y)=32

(1152/y^2)=32

y^2=1152/32

y^2=36

y=6

so x will be

x*y=24

x*6=24

x=24/6

x=4

in the same way

z will be

z=8

so

x=4

y=6

z=8

x=4

z=8