Question

of three sides of a triangle one is twice the smallest and another is thrice the smallest,find all the angles
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Answer 1

Answer:

the triangle first side is (a)

the triangle first side is (a)triangle second side is (2a )

the triangle first side is (a)triangle second side is (2a )triangle third side is (3a)

so the angle front of smallest side is X degree

angle front of the second side is 2x degree

angle front of the third side is 3x degree

so that three angle are-----

( x°,2x°,3x°)

we know that the sum of all angles of a triangle is 180 °

so,

(x°+2x°+3x°). = 180°

6x=180°

x=30°. [x= 30°]

[2x=60°]

[3x=90°]

i hope it is help for you.....................

Answer 2

Given:-

• Three sides of a triangle one is twice the smallest and another is thrice the smallest.

To Find :-

• All the three sides of the triangle

Solution :-

We Know that a Triangle has three sides and all the three sides add upto the sum of 180°

• Let smallest angle be x

• The Angle twice to the smallest be 2x

• The angle thrice to the Smallest be 3x

Accordingly, The all three sides of a Triangle add to a sum of 180°, So

• x + 2x + 3x = 180°

• 6x = 180°

• x = 30°

Since the smallest angle is 30° Other angles = 2x = 2*30 = 60° and 3x = 3*30 = 90°.

$\sf{ \underline{ \red{The \: Angles \: are \: \ < 30 \: < 60 \: < 90}{} }{} }{}$