of three terms are in A.P and sum of all three terms is 21. Find 2nd term.
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let the three term of A.P are a,a +d,a+2d. now , as per the question ,
a+a+d+a+2d=3a+3d=21
i.e. a+d=7or ,d=7-a
now,a(a+2d) -(a+d)=6
a{a+2(7-a)}-7=6
a{a+14-2a}=13
a{14-a}=13
14a-a2=13
a2-14a+13=0
by factorising,we get
a=13,1
d=7-a
for a= 13,1d=7-13,7-1= - 6 ,6
respectively
now,three are two A'p s a,a +d,a + 2d for
two values of a and d
13,7,1and1,7,13
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