Of two numbers ,1/5th of greater is equal to 1/3of the smallerand their sum is 16.the numbers are
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Assume x/5 = y/3 i.e x = 5y/3 ---- (i)
x + y = 16 -------- (ii)
Substitute (i) in (ii)
5y/3 + y = 16
8y = 48
y = 6
Place value of y = 6 in (ii)
x = 10
x + y = 16 -------- (ii)
Substitute (i) in (ii)
5y/3 + y = 16
8y = 48
y = 6
Place value of y = 6 in (ii)
x = 10
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