Question

Of two squares the sides of the larger are 5cm longer than those of the smaller and the area of the small and the area of larger is 55cm more what is the length of the side of each

Answer 1

Answer:

Square 1 = s1= x cm

Square 2 sides = s2=( x+5)cm

Area A1= x^2 cm^2

Area of A2=( x^2+ 55) cm^2

So,

x^2+ 55=(x+5)^2

x^2+ 55= x^2+10x+25

x^2+10x+25-x^2-55=0

10x-30=0

10x=30

x= 30/10 = 3 cm

So, the sides of s1 = 3cm

And s2 = x+5= 3+ 5= 8 cm

A1= x^2 cm^2= 3^2= 9 cm^2

A2=( x^2+ 55) cm^2= 3^2+55= 64 cm^2

Answer 2

Answer:

Mark me Brainlest

Explanation:

Write the Answers in the paper