Of two unequal chords of a circle prove that greater chord is nearer to the circle
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Answered by
1
Answer:
it is true
Step-by-step explanation:
the chord at edge will have length 0 and ata distance r
the chord comes nearer to the centre with increase in length
hence at centre the chord become diameter of length 2r and distance 0
Answered by
1
Answer:
this statement is true
Step-by-step explanation:
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