Question

of we increase 20% in numerator and 25% in denominator of a fraction then it is 3\5, then the original fraction is​

Answer 1

If increasing the numerator by 20% and the denominator by 25% gives 3/5 then the original fraction is 5/8.

Step-by-step explanation:

Let the original numerator be "x" and the original denominator be "y".

(1). Firstly, the numerator is increased by 20% i.e.,

x + (20% * x)

= x + (x/5)

= (5x+x) / 5

= 6x / 5 ...... (i)

(2). Secondly, the denominator is increased by 25% i.e.,

x + (25% * x)

= x + (x/4)

= (4x+x) / 4

= 5x / 4 ...... (ii)

It is given that after the increasing of numerator and denominator the fraction becomes 3/5.

Therefore, from (i) & (ii), we can write the final equation as,

$\frac{\frac{6x}{5}}{\frac{5y}{4}} = \frac{3}{5}$

⇒ $\frac{24x}{25y} = \frac{3}{5}$

⇒ $\frac{x}{y} = \frac{3 * 25}{5 * 24}$

⇒ $\frac{x}{y} = \frac{5}{8}$

Thus, the original fraction is 5/8.

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If the numerator of fraction is increased by 25% and the denominator increased by 10% it becomes 2/5 find the original fraction?

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Answer 2

Answer:

the original fraction is​ 5/8

Step-by-step explanation:

Let n be the original numerator and d be the original denominator.

The numerator is increased by 20%. So, the new numerator is 1.20 of the original numerator.

We write this as: 1.20n

Similarly, the new  denominator is 1.25 of the original denominator.

We write this as: 1.25d

Since the new fraction is 3/5 we equate the respective values of both the numerator and denominator as follows:

1.20n = 3

n = 3/1.20 = 2.5

1.25d = 5

d = 5/1.25 = 4

The original fraction is given by: n/d = 2.5/4

Simplifying we have:

(2.5/4)2 = 5/8