Question

of
x= 3+58 find
find the value of
x2x
x2​

Answer 1

Given :-

X=$3 + \sqrt{8}$

What to find out = value of $(x {}^{2} + \frac{1}{ {x}^{2} })$

Solution :-

$x {}^{2} + \frac{1}{ {x}^{2} } = (x + \frac{1}{x} ) {}^{2} - 2 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (3 + \sqrt{8} + \frac{1}{3 + \sqrt{8} } ) {}^{2} - 2 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (3 + \sqrt{8} + 3 - \sqrt{8} ) {}^{2} - 2 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (6) {}^{2} - 2 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 36 - 2 \\ \\ {x}^{2} + \frac{1}{x {}^{2} } = 34 \: \: \: \: \: \: \: \: ans$

Answer 2

hope this answer helps you