Question

of x+y=12,and xy=32 then findx^2+y^2=?​

Answer 1

Answer:

80

Step-by-step explanation:

JUST SEE THE TWO EQUATIONS OBTAINED

1. x+y=11
2. x×y=32

SO,STEP1》SQUARE BOTH SIDES OF 1ST EQUATION

=(x+y)^2

=x^2+y^2+2xy=144

STEP 2.PUT THE VALUE OF XY IN EQUATION 2

x^2+y^2+2×32=144

x^2+y^2=144-64

x^2+y^2= 80

OK.. FRIEND

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