Question

of y = ( 1)/ ( ax+b) then find 3rd order derivative​

Answer 1

dy/ dx=-a/(ax+b)^2(in division rule of derivative eg on differentiating u/v in formula {(du/dx)v-u(dv/dx)}\v^2

since a is content so 0 and - then negative sign appear in differentiating ax+b)

d^2y/dx^2=2a/(ax+b)^3

d^3y/dx^3=-6a/(ax+b)^4

Answer 2

$\frac{dy}{dx} = \frac{ - a}{ ({ax + b})^{2} } \\ \frac{ {d}^{2}y }{d {x}^{2} } = \frac{ 2 {a}^{2} }{( {ax + b})^{3} } \\ \frac{ {d}^{3}y }{d {x}^{3} } = \frac{ - 6 {a}^{3} }{ ({ax + b})^{4} }$