Question

OF2(g) + H2O(g) -------------> O2(g) + 2HF(g) so calculate ∆n​

Answer 1

Answer:

OF2(g) + H2O(g) → 02(g) + 2HF(g) at 298 K. The standard enthalpies of formation in kJ molare: OF2 (g) = 20, H20 (g)=-250 and HF (g)=-270 (R-8.314 JK-1 mol-1) [Ans. AUⓇ =-312.5 kJ]

Answer 2

Answer:

OF2(g) + H2O(g) → 02(g) + 2HF(g) at 298 K. The standard enthalpies of formation in kJ molare: OF2 (g) = 20, H20 (g)=-250 and HF (g)=-270 (R-8.314 JK-1 mol-1) [Ans. AUⓇ =-312.5 kJ]