Question

Offices in Delhi are open for five days in a week (Monday to Friday). Two employees ofan office remain absent for one day in thesame particular week. Find the probability that they remain absent on :(i) the same day (ii) consecutive day(iii) different days.​

Answer 1

Step-by-step explanation:

Given Offices in Delhi are open for five days in a week (Monday to Friday). Two employees of an office remain absent for one day in the same particular week. Find the probability that they remain absent on :(i) the same day (ii) consecutive day(iii) different days.

• So total possible outcomes will be (for first person it will be 5 days and can be absent on any days. So for second person also it will be 5 days.
• So we get 5 x 5 = 25
• So the possibilities can be
• MM, MW, MTh, MF, TM, TT, TW, TTh, TF, WM, WT, WW, WTh, WF, ThM, ThT,ThW, ThTh, ThF, FM, FT, FW, FTh,FF
• Now probability for the same day will be MM, TT, WW, ThTh, FF
• So the number of favourable outcomes = 5
• So total outcomes = 25
• So probability = 5/25
•                      = 1/5
• Now probability for the consecutive day will be MT,TM, TW,, WT,, WTh, ThW, ThF, FTh
• So the number of favourable outcomes is 8
• So probability = 8/25
• Now probability for different day will be 1 – Probability(same day)
•                                                                = 1 – 1/5
•                                                                = 4/5

Reference link will be

https://brainly.in/question/15716115

Answer 2

Answer:

4/5is the final answer