Question

ofk
6. If x= 3k +2 and y= 2k - 1 is a solution of the equation 4x-3y-1=0
find the value of k​

Answer 1

It is given that 4x−3y+1=0

Now by substituting the value of x and y in the equation

4(3k+2)−3(2k−1)+1=0

On further calculation

12k+8−6k+3+1=0

6k+12=0

So we get

6k=−12

By division

k=−2

hope it helps

@jayanti3347

Answer 2

Answer:

-5/3

Step-by-step explanation:

Since x = 3k+2 and y = 2k-1 is the solution of equation 4x-3y-1 = 0, they should satisfy the equation.

So substituting values of x and y in the equation

4(3k+2)-3(2k-1)-1 = 0

12k+8-6k+3-1 = 0

6k+10 = 0

6k = -10

k = -10/6 = -5/3