Math, asked by chouhanbharat9612, 11 months ago

Ofter 11 years sahil age will be 46 years. Today sunny age is 7 years more than sahil age. At prasent sumit age and sunny age are in the ratio of 5:7.what was the sumit age 6 years before

Answers

Answered by PanditRavan
1

Answer:

(24)

Step-by-step explanation:

Present Age of Sahil = 46-11=35

Sunny's present age = 35 (Sahil's age) + 7 = 42

Raito of Sumit and Sunny's age

5:7

Sunny's present age 42 then value of 75 is = 42÷7 = 6

then

Sumit present age is 5×6= 30

30-6=24 age of Sumit before 6 years

Answered by Syamkumarr
0

Answer:

Sumit's age before 6 years = 24 years

Step-by-step explanation:

Given data

after 11 years Shil's age will be 46 years

present Sunny's age is 7 years more than Shil's sge

the ratio of sumit and Sunny's age = 5:7

here we need to find Sumit's age 6 years before  

from given data

11 years after Shils age will be 46 years

⇒ Sahil's present age = 46 - 11 = 35 years  

Sunny's age is 7 years more than Sahil's age

⇒ Sunny's present age = 35 + 7 = 42 years

the ratio of the Sumit and Sunny age = 5:7

let's consider that 5x and 7x are be the ages of Sumit and Sunny

⇒  7x = 42    [ ∵ Sunny's age = 42 ]  

       x = 6

Sumit's age = 5x = 5(6) = 30 years

sumit's present age = 30 years                

Sumit's age before 6 years = 30 - 6 = 24 years

Similar questions