Question

Oh
2. Find the simple interest R$ 25,000 at 8-
per annum
for 3 years​

Answer 1

Answer :

• SI = Rs 6000
• Amount = Rs 31000

Given :

• Amount on Rs 25000
• For 3 years
• At 8% per annum.

To do :

• Calculation of the Simple Interest.

We can :

Do this in two methods :

• Unitary method.
• Using formula.

Method 1

Here, Rate of interest = 8%

Therefore, Interest on Rs 100 for 1 year = Rs 8

$\begin{gathered} \rm \therefore \: Interest \: on \: Rs \: 1 \: for \: 1 \: year = Rs \: \dfrac{8}{100} \\ \\ \rm \: \therefore \: Interest \: on \: Rs \: 25000 \: for \: 1 \: year \\ \rm= Rs \: \bigg( \dfrac{8}{100} \times25000 \bigg) \\ \bf = Rs \: 2000 \\ \\ \rm\therefore \: Interest \: on \: Rs \: 25000 \: \: for \: 3 \: year \\ \rm = Rs \: (2000 \times3) \\ \bf = Rs \: 6000\: \end{gathered}$

Thus, Required Simple Interest = Rs 6000

Amount = Principal + Interest

= 25000 + 6000

= 31000

Method 2

( R ) Rate of interest = 8%

( P ) Principal = Rs 25000

( T ) Time = 3 years

$\begin{gathered} \rm \therefore \: Simple \: Interest \: (SI) = \dfrac{ \: P \: \times R \: \times \: T \: }{100} \\\\ = \dfrac{25000 \times 8 \times 3}{100} \\ \\ \large\bf= 600\end{gathered}$

Therefore, Amount = Principal + Interest

= 25000 + 6000

= 31000

Therefore,

• Simple Interest = Rs 6000
• Amount = Rs 31000

Answer 2

Question :

• Find the Simple Interest on Rs 25000 at 8% per annum for 3 years.

Given :

• Principal (P) = Rs 25000
• Rate (R) = 8%
• Time (T) = 3 years

To Find :

• Simple Interest

Solution :

⟾ Simple Interest = P × R × T / 100

⟾ Simple Interest = 25000 × 8 × 3 / 100

⟾ Simple Interest = 250 × 8 × 3

⟾ Simple Interest = 250 × 24

⟾ Simple Interest = Rs 6000

Thus Simple Interest is Rs 6000

___________________

★ Additional Info :

$\large\boxed{\begin{array}{cc}\large\sf\dag \: {\underline{More \: Formulae}} \\ \\ \bigstar \: \sf{Principle :- \dfrac{SI \times 100}{R \times T}} \\ \\\bigstar \: \sf{Rate \: of \: Interest :- \dfrac{SI \times 100}{P \times T}} \\ \\ \bigstar \: \sf{Time :- \dfrac{SI \times 100}{P \times R}}\end{array}}$