oh-ch3+ o----k2cr2o7/h+
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B CH3COCH3
2º alcohols give ketones with acidified
K2Cr2O7. Ketones containing CH3CO-type
perform haloform.
Here, Y is formed by the oxidation of propan
2-ol. So, it must be acetone. The reaction is given below:
CH3CH(OH)CH3
K₂Cr₂O7
CH3COCH3 ² CHI3
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