Question

oheyy solution plzzzzz​

Answer 1

a) Between 1 and 100,

Between 1 and 100, totally 25 prime numbers are present.

Probability P(E) :

Number of trials in which the event happened

Total number of trials

P(E) of getting prime numbers :

$\frac{25}{100} = \frac{1}{4}$

b) Between 1 and 100,

Between 1 and 100, totally 10 multiples of 10 are present.

Therefore,

P(E) of getting multiple of 10 :

$\frac{10}{100} = \frac{1}{10}$

c) Between 1 and 100,

Between 1 and 100, totally 10 perfect square numbers exist.

Therefore,

P(E) of getting a perfect square number :

$\frac{10}{100} = \frac{1}{10}$

d) Between 1 and 100,

Between 1 and 100, totally 50 even numbers are present.

Therefore,

P(E) of getting an even number :

$\frac{50}{100} = \frac{1}{2}$

Answer 2

Answer:

Step-by-step explanation

Let the 100 cards with numbers 1, 2 , 3, 4,.. 100 are placed in a box and mixed.

Let the probability of event(E) if one card is drawn randomly from box is P(E)

2. (a).  Question is not visible correctly.

2. (b)

E = Drawn card is multiple of 10.

P(E) = Total cards with multiple of 10 ÷ Total cards

P(E) = 10 ÷ 100 = 1/10 = 0.1

2. (c)

E = Drawn card is a perfect square.

P(E) = Total no. of perfect square between 1 to 100 ÷ Total no. of cards

P(E) = 10/100 = 0.1

2. (d)

E = Drawn card number is an even number.

P(E) = Total even numbers between 1 to 100 ÷ Total no. cards

P(E) = 50/100 = 0.5