Question

ऑक्जेलिक अम्ल (तुल्यांक भार = 63) के 0.63 ग्राम, 250 मिली. विलयन में घुले
हैं। विलयन की नॉर्मलता ज्ञात कीजिए।​

Answer 1

Given:

ऑक्जेलिक अम्ल (तुल्यांक भार = 63) के 0.63 ग्राम, 250 मिली. विलयन में घुले

हैं। विलयन की नॉर्मलता ज्ञात कीजिए।​

0.63 gram oxalic acid(equivalent weight=63)is dissolved in250ml of solution.find out the normality of the solution

To find:

Normality of the solution

Solution:

The weight of Oxalic acid = 0.63 gm

The equivalent weight of Oxalic acid = 63

The volume of the solution = 250 ml

To solve the above-given problem we will use the following formula of normality:

$\boxed{\bold{Normality(N)= \frac{Gram\:eq.\:of\:solute}{Volume\: of\: solution \:in\: litre} = \frac{Weight}{Eq. \:weight} \times \frac{1000}{V(ml)} }}$

Now, on substituting the given values in the formula above, we get

$Normality = \frac{Weight}{Eq. \:weight} \times \frac{1000}{V(ml)} }}$

$\implies Normality = \frac{0.63}{63} \times \frac{1000}{250} }}$

$\implies Normality = \frac{0.63}{63} \times 4}}$

$\implies Normality = \frac{63}{6300} \times 4}}$

$\implies Normality = \frac{1}{100} \times 4}}$

$\implies \bold{Normality = 0.04\:Eq./L\:or\:N}$

Thus, the normality of the solution is → 0.04 N or Eq./L.

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