Question

ointegral ² 5x⁴ plz help​

Answer 1

Answer:

The expression 3x^4+5x^3-7x^2+2x+23x

4

+5x

3

−7x

2

+2x+2 divided by x^2+3x+1x

2

+3x+1

TO FIND :

The quotient for the given expression by using Long Division Method.

SOLUTION :

Given that 3x^4+5x^3-7x^2+2x+23x

4

+5x

3

−7x

2

+2x+2 divided by x^2+3x+1x

2

+3x+1

Here by using the Long Division Method we have to find the quotient.

3x^2-4x+23x

2

−4x+2

_________________________

x^2+3x+1x

2

+3x+1 ) 3x^4+5x^3-7x^2+2x+23x

4

+5x

3

−7x

2

+2x+2

3x^4+9x^3+3x23x

4

+9x

3

+3x2

_(-)__(-)___(-)_________

-4x^3-10x^2+2x−4x

3

−10x

2

+2x

-4x^3-12x^2-4x−4x

3

−12x

2

−4x

___(+)___(+)___(+)______

2x^2+6x+22x

2

+6x+2

2x^2+6x+22x

2

+6x+2

__(-)___(-)___(-)_______

0

__________________

Therefore the quotient when the given expression 3x^4+5x^3-7x^2+2x+23x

4

+5x

3

−7x

2

+2x+2 divided by x^2+3x+1x

2

+3x+1 is 3x^2-4x+23x

2

−4x+2

∴ the quotient is 3x^2-4x+23x

2

−4x+2