Math, asked by raheemakhtar270, 3 months ago

OJO 50 men can complete a work in 30 days, if 10 men leave the work. In
how many days will the remaining men complete the work.
Unit - 6 Unitary Method
121​

Answers

Answered by preritagrawal08
1

You did not mention when did the 10 men leave the job. If they left the job without working even for one day the 40 men will complete the work in 50x30 man-days/40 men = 37.5 days.

If the 10 worked for 1 day and then left, the remaining 40 men will complete the work in (1500–10)/40 = 1+37.25 = 38.25 days.

If the 10 worked for 2 days and then left, the remaining 40 men will complete the work in (1500–20)/40 = 2+37 = 39 days.

If the 10 worked for 3 days and then left, the remaining 40 men will complete the work in (1500–30)/40 = 3+36.75 = 39.75 days.

If the 10 worked for 4 days and then left, the remaining 40 men will complete the work in (1500–40)/40 = 4+36.5 =40.5 days.

If the 10 worked for 5 days and then left, the remaining 40 men will complete the work in (1500–50)/40 = 5+36.25 = 41.25 days.

If the 10 worked for 6 days and then left, the remaining 40 men will complete the work in (1500–60)/40 = 6+36 = 42 days.

If the 10 worked for 7 days and then left, the remaining 40 men will complete the work in (1500–70)/40 = 7+35.75 = 42.75 days.

If the 10 worked for 8 days and then left, the remaining 40 men will complete the work in (1500–80)/40 = 8+35.5 = 43.5 days.

If the 10 worked for 9 days and then left, the remaining 40 men will complete the work in (1500–90)/40 = 9+35.25 = 44.25 days.

If the 10 worked for 10 days and then left, the remaining 40 men will complete the work in (1500–100)/40 = 10+35 = 45 days.

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