Question

ok pls send fast its urgent guys common​

Answer 1

Answer:

b(c-d)²+a(d-c)+3c-3d

b(c²+d²-2cd)+ad-ac+3c-3d

bc²+bd²-2bcd+ad-ac+3c-3d

Answer 2

Answer:

bc²-2bcd+bd²-ac+ad+3c-3d

Step-by-step explanation:

b(c-d)²+a(d-c)+3c-3d

b(c-d)(c-d)+a(d-c)+3c-3d

b[(c(c-d)-d(c-d)]+a(d-c)+3c-3d

b(c²-cd-d(c-d)]+a(d-c)+3c-3d

b(c²-2cd+d²)+a(d-c)+3c-3d

bc²-2bcd+bd²+a(d-c)+3c-3d

bc²-2bcd+bd²+a(-c+d)+3c-3d

= bc²-2bcd+bd²-ac+ad+3c-3d

Hope it helps you

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