Question

Ok Short asupf dkfpv

Answer 1

Answer:

In ΔBEC, D is mid-point of BC and from converse of mid-point theorem. i.e. A line i.e. DF drawn through the mid-point D of BC and parallel to BE bisects the third side i.e. EC at F. Now, F becomes the mid-point of CE. CF = 1/2 CE

CF = 1/2(1/2 AC)

[E is mid-point of AC = AE = EC = 1212 AC]

= CF = 1/4 AC