OK.. Well I'm not asking too hard
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- Three digit natural numbers divisible by 5 are :
- 100 , 105 , 110 , ..........., 995.
- Here, a = 100 , d = (105-100=5) , tn = 995
- tn = a + (n-1)d {formula}
- ↝ 995 = 100 + (n-1)×5
- ↝ 995 = 100 + 5n -5
- ↝ 995 = 95 +5n
- ↝ 5n = 995-95
- ↝ 5n = 900
- ↝ n= 900/ 5
- ↝ n= 180
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