Question

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Answer 1

Step-by-step explanation:

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Answer 2

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$a \times ( \frac{3}{4} {)}^{2} + b \times \frac{3}{4} - 6 = 0$

$\frac{9}{16} a + \frac{3b}{4} = 6$

$\frac{9a + 12b}{16} = 6$

$9a + 12b - 9 = 0$

$3a + 4b = 32...........(eq.1)$

Again , (-2) is a root of the given equation therefore, we have

$ax( { - 2})^{2} + bx( - 2) - 6 = 0$

$4a - 2b = 6$

$2a - b = 3.............(eq.2)$

On multiplying eq.2 by 4 and adding the result with eq.1 , we get

$3a + 4b + 8a + 4b = 32 + 12$

$11a = 44$

$a = \frac{44}{11}$

$a = 4$

Putting the value of a in eq.2, we get

$2 \times 4 - b = 3$

$8 - b = 3$

Hence, the values of a and b are 4 and 5 respectively

$b = 4$

$b = 5$