Question

olar mass of NaOH = 40 g mol, Molar mass of H 0,02H0 - 126
1) To Calculate of NaOH:
1000 mL IMHCO, - 80 g NaOH
10 mL IMH.CO - 0.8 g NaOH
10 mL0.05MH.C.0, 0.04 g NaOH
Therefore 0.04 g of NaOH is present in
mL (C.B.R) of NaOH of unkonwn molarity
(mL of NaOH solution contains 0,04 g of NaOH
1000 0.04
1000 ml NaOH solution contains - C.BR gof NaOH
1000*0.04
gof NaOH
To calculate molarity of NaOH:​

Answer 1

Answer:

No if mole of P4 molecule = given wt/molar wt

= 124/124 = 1 mole

hence,

no of P4 molecules =mole × Avogadro constant

= 1 × 6.023 × 10²³ = 6.023 × 10²³

no of P atoms in P4 =4 × mole of P4 × Avogadro constant

= 4 × 1 × 6.023 × 10²³

= 24.092 × 10²³

= 2.4092 × 10²⁴