Math, asked by mdtoufiquesheikh0292, 7 months ago

ole 4
The decomposition of N, 05 in CCl, at 318K has been studied
5
to 2.08 mol L . The reaction takes place according to the equation
2 1,05 (g) → 4 NO, (g) + O2(g)
and seconds. What is the rate of production of NO, during this period?
1
AN,0.1)
1 (2.08 -2.33) moll
monitoring the concentration of N, O, in the solution. Initially the
concentration of N,0. is 2.33 mol Land after 184 minutes, it is reduced
Calculate the average rate of this reaction in terms of hours, minutes​

Answers

Answered by dubeyshovit2020
0

Answer:

please mark brainlest

Step-by-step explanation:

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