Question

Ole ole
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Answer 1

Step-by-step explanation:

Area of EFQ = 1/2 * base * height

= 1/2 * 80 * 60

= 40 *60

=2400 sq. m

Area of trap. DEQR = 1/2 * EQ + RP * QR

= 1/2 * 100 * 70

= 3500 sq. m

Area of CDR = 1/2 * 40 * 40

= 80 sq. m

Area of APF = 1/2 * 30 * 50

= 750 sq. m

Area of rect. ABSP = 50 * 130

= 6500 sq. m

Area of BCS = 1/2 * 30 * 50

= 750 sq. m

Now,

Area of ABCDEF = ar(EFQ) + ar( DEQR) + ar(CDR) + ar( APF) + ar( ABSP) + ar (BCS)

= 2400 + 3500 + 80 + 750 + 6500 + 750

= 13980 sq. m

Your answer is 13980 sq. m.

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Answer 2

Area of EFQ

= 1/2 * base * height

= 1/2 * 80 * 60 = 40 *60 =2400 sq. m

Area of trap. DEQR

= 1/2 * EQ + RP * QR

= 1/2 * 100 * 70 = 3500 sq. m

Area of CDR = 1/2 * 40 * 40 = 80 sq. m

Area of APF = 1/2 * 30 * 50 = 750 sq. m

Area of rect. ABSP = 50 * 130 = 6500 sq. m

Area of BCS = 1/2 * 30 * 50 = 750 sq. m

Now,

Area of ABCDEF

= ar(EFQ) + ar( DEQR) + ar(CDR) + ar(APF) + ar( ABSP) + ar (BCS)

= 2400 + 3500 + 80 + 750 + 6500 + 750

= 13980 sq. m

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