OLISILIUD
5. 20% of dolls produced in a factory were
defective, 25% of the remaining were damaged.
If 4800 dolls were left over, what was the original
number of dolls?
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Answer:
7440 dolls
Step-by-step explanation:
Given, % ( defective dolls ) = 20%
% ( damaged dolls ) = 25%
Therefore, % ( Favourable dolls ) = 100% - 20% + 25% = 100% - 45% = 55%
Let the original number of dolls be x
no ( Unfavourable dolls ) = 4800
Therefore, x = 4800 + 55% of 4800
, x = 4800 + 55/100 * 4800
, x = 4800 + 2640
, x = 7440 dolls
Hence, the original number of dolls are 7440 dolls
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