Math, asked by shannubhagat2, 10 months ago

OLISILIUD
5. 20% of dolls produced in a factory were
defective, 25% of the remaining were damaged.
If 4800 dolls were left over, what was the original
number of dolls?​

Answers

Answered by shridharbelagavi900
2

Answer:

7440 dolls

Step-by-step explanation:

Given, % ( defective dolls ) = 20%

% ( damaged dolls ) = 25%

Therefore, % ( Favourable dolls ) = 100% - 20% + 25% = 100% - 45% = 55%

Let the original number of dolls be x

no ( Unfavourable dolls ) = 4800

Therefore, x = 4800 + 55% of 4800

, x = 4800 + 55/100 * 4800

, x = 4800 + 2640

, x = 7440 dolls

Hence, the original number of dolls are 7440 dolls

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