Question

olve the following equations and 7(x - 2) = 2(3x + 1)​

Answer 1

Answer:

• In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.
• 3 x + 1 − 1 2 = 2 3 x − 1 , x ≠ − 1 , 1 3 3x+1−12=23x−1,x≠−1,13 ⇒ (5 - x)(3x – 1) = 4x + 4 ⇒ -3x2 + 16x – 5 = 4x + 4 ⇒ 3x2 - 12x + 9 = 0 ⇒ 3x2 – 3x – 9x + 9 = 0 ⇒ 3x(x – 1) -9(x – 1) =0 ⇒ (3x – 9)(x – 1) = 0 ⇒ x = 1, 3Read

c-equations-by-factorization-3-x-1-1-2-2-3x-1-x-1-1-3

Answer 2

Answer:

Question :-

Solve the following equations and 7(x - 2) = 2(3x + 1)

Required Solution :-

$7(x - 2) = 2(3x + 1)$

$7 \times x - 7 \times 2 = 2 \times 3x + 2 \times 1$

$7x - 14 = 6x + 2$

$7x - 6x = 2 + 14$

$x = 16$