Question

olve : -
x + y = 3, 2x + 5y = 12
3x - 5y + 1 = 0, 2x – y + 3 = 0
x + 3y = 8, 3x = 2 + 2y
4x - 5y = - 4, 3x = 2y - 3
3 - (x - 5) = y + 2, 2(x + y) = 4 – 3y​

Answer 1

Answer:

:x+y=3;2x+5y=12

2x+5y=12, we have x+y=3

when y=0⇒x=3, when x=0⇒y=3

x03

y30

2x+5y=12⇒y=

5

12−2x

x1−4

y24

∴ The lines intersect at a point p(1,2) Hence x=1,y=2

solution