Math, asked by saritayadav6772, 7 days ago

OM is an altitude of triangleOPQ and PM=MQ. Prove that anglePOM = angle QOM.

Answers

Answered by imposterqueen69

0

Answer:

triangle A'B'C is an equilateral triangle A=60°

ABEC is a cyaic quadrilateral

angel A + Angle E =180°

(sum of opposite angels)

60°+angel E =180°-60°=120°

m(BEC=120

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