Question

om the given data
0-20 20-40 40-60 60-80
15
р
18 10
eservations of the data are
5
of mode is 52. Then find the value of p'.​

Answer 1

Answer:

Class = 0-20, 20-40, 40-60, 60-80, 80-100

Frequency = 15, 6, 18, 10, 5

The maximum class frequency is 18 and the class corresponding to this frequency is 40-60.

So, the modal class is 40-60.

Here, lower limit of modal class l= 40

class size h= 20

Frequency of the modal class f_{1}=18f

1

=18

Frequency of class preceding the modal class f_{0}=6f

0

=6

Frequency of class succeeding the modal class f_{2}=10f

2

=10

We need to calculate the mode

Using formula of mode

Mode =l+(\dfrac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}})\times hMode=l+(

2f

1

−f

0

−f

2

f

1

−f

0

)×h

Put the value into the formula

Mode=40+(\dfrac{18-6}{2\times18-6-10})\times20Mode=40+(

2×18−6−10

18−6

)×20

Mode=52Mode=52

Hence, The mode is 52.