omas’s math class held a raffle. The student who picked the ticket with a pair of equivalent equations on it would win. Which is the winning ticket?
Answers
Given : omas’s math class held a raffle. The student who picked the ticket with a pair of equivalent equations on it would win.
To Find : Which is the winning ticket
x²- 3xy + 4 -2 x²= -x² - 2xy -xy + 4
7y²- yz + 4 - 2yz = 7y² - 2yz + 4yz.
3a²- ab + 3 - 3ab = 6a²- 2ab + 3 - 2ab
9s² - st + 5 - 3st = 6s² - 3st + 5 + 3s²
Solution:
x²- 3xy + 4 -2 x²= -x² - 2xy -xy + 4
LHS = x²- 3xy + 4 -2 x² = - x²- 3xy + 4
RHS = -x² - 2xy -xy + 4 = - x²- 3xy + 4
LHS = RHS
7y²- yz + 4 - 2yz = 7y² - 2yz + 4yz.
LHS = 7y²- yz + 4 - 2yz = 7y²- 3yz + 4
RHS = 7y² - 2yz + 4yz. = 7y²- 2yz
LHS ≠ RHS
3a²- ab + 3 - 3ab = 6a²- 2ab + 3 - 2ab
LHS = 3a²- ab + 3 - 3ab = 3a²- 4ab + 3
RHS = 6a²- 2ab + 3 - 2ab = 6a²- 4ab + 3
LHS ≠ RHS
9s² - st + 5 - 3st = 6s² - 3st + 5 + 3s²
LHS = 9s² - st + 5 - 3st = 9s² - 4st + 5
RHS = 6s² - 3st + 5 + 3s² = 9s² -3st + 5
LHS ≠ RHS
x²- 3xy + 4 -2 x²= -x² - 2xy -xy + 4 is the Winning Ticket
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