on 1st jan 2016, sanika decides to save $10, $11 on second day, $12 on third day. If she decides to save like this, then on 31st dec 2016 what would be her total saving?
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It's arithmetic progression
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it's goes on like 10$,11$,...........,375$
since 2016 is a leap year
(Tn = a+(n-1)*d
a= 10
n= 366
d= 1
last term = 375)
sum=(n/2)*(2a+(n-1)*d)
sum = (366/2)*((2*10)+(365)*1)
sum = (183)*(385)
sum = 70455 $
--------------------------------------
it's goes on like 10$,11$,...........,375$
since 2016 is a leap year
(Tn = a+(n-1)*d
a= 10
n= 366
d= 1
last term = 375)
sum=(n/2)*(2a+(n-1)*d)
sum = (366/2)*((2*10)+(365)*1)
sum = (183)*(385)
sum = 70455 $
sneharajsharma:
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