Question

On 1st Jan 2016, Sanika decides to save rupees 10, rupees 11 on second day, rupees12 on third day. If she decides to save like this, then on 31st Dec 2016 what would be her total saving? Solve the word problem

Answer 1

Step-by-step explanation:

the first thing is that 2016 was a leap year so there must be 29 days in February and 366 days in the year .

and the saved amount of her 366 th day would be 375

and now

$total \: amount = \frac{(375 + 10)366}{2} \\ = 385 \times 183 \\ = 70455$

Answer 2

Answer:

Total saving= 70,455 Rs

Step-by-step explanation:

Sanika saving pattern from 1st January 2016

10,11,12,13...

It forms an AP,with first term a= 10

common difference d= 1

total days n= 366

Since,2016 is leap year

Sum of AP for n terms

$\boxed{S_n = \frac{n}{2} \bigg(2a + (n - 1)d\bigg) }\\ \\ = \frac{366}{2} (2 \times 10 + 365 \times 1) \\ \\ = 183(20 + 365) \\ \\ = 183 \times 385 \\ \\ = 70455 \: Rs$

On 31st Dec 2016 her total saving is 70,455 Rs

Hope it helps you.