Question

On 1st jan 2016 , sanika desires to save Rs10 , Rs11 on second day , Rs12 on third day . If she decide to save like this , then on 31st Dec 2016 what would be her total saving?​

Answer 1

Sanika saves Rs 10 on the first day Rs 11 on second day Rs 12 on third day and so on

The amount of saving is 10,11,12,13....................

This is an A.P with

a=10

d=11-10=1

In the leap year 2016 there are 366 days

Let's find the total amount of saving i.e S366

We know that,

Sn= n/2 [2a +(n-1)×d]

=366/2 [20+365]

= 183×385

= 70455

S366=₹70455

Answer 2

This is an A.p. with a=10 ,d =1

to find sn

we know that 2016 is a leap year

then there are 366 days in it

Sn =n/2(2a+(n-1)d)

s366 = 366/2(2×10+(366-1)1)

s366 = 183(20+365)

s366 = 188×385

s366 = 70,445rs

hence, Danika saves rs 70,445 in the year 2016

Hope it helps u ^_^ ^_^ ^_^

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