Math, asked by pallashiva99, 19 days ago

on 2
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The sum of ages of a and b is 8 years. 1 year ago the age of a is n times of age of b. The present age of a=Sn-1(n-1), present age of b is b=Sn+(n+1)(n-1)
7years

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Answered by 0sumitramgharia855

0

Answer:

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