Physics, asked by sounak0101, 4 months ago

on 2
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An ammonia ice plant operates between condenser and evaporator temperature of 35 and
-16°C respectively. It produces 5 tons of ice per day from water at 25°C to ice at -5°C. The NH3
enters the compressor as dry saturated vapor. Use the following table and find
(i) Capacity of the plant in Tons
out of
question
(ii) Mass flow rate of refrigerant in kg/s
(ii) COP
t(°C)
P (bar) Liquid
vapor .
hf kJ/kg Sf
kJ/kg.K
hg kJ/kg Sg
Ng
kJ/kg.K m3/kg
|-16
2.26
107.83
0.4397
1425.28 5.5693
0.5303
35
13.5
347.5
1.2821
1471.43 4.93
0.0906
Take Cp of ammonia vapor as 2.8 kJ/kg.K
anto
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Answers

Answered by dndnfkkvjv
0

Answer:

The ball is dropped from a point A at a height h above the surface. Thus during the entire motion, let the time taken by the ball to move move from A to B be t¹ from B to C and C to B be t ² , from C to D be t³ , from D to C be t ⁴ , and from B to A be t5

Let T be the time period of the complete motion.

Now for the motion A to B; h=0+ \frac{1}{2}g(t¹) ²

⟹ t ¹ = \frac{√2h}{g}

Similarly , t ³= t ⁴=  t 5 =  t ¹ = \frac{√2h}{g}

As the time period of the particle executing SHM inside the tunnel is given by t=2π \frac{√Re}{g}

\textsf{Thus the time period of the motion of the ball inside the tunnel  i.e   B to C and  C to B,  } t ² =2π \frac{√R}{g}

Now the total time period of the motion T= t ¹+ t² +  t³+[tex]t⁴+ t5

==> T = 2π \frac{√R}{g} + 4 \frac{√2h}{g}

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