Question

On 5 April Kolkata had a day temrature of 33°c and on the same day ladhak had a day temrature of 23°f find the difference in °c (use the formula

Answer 1

heya....


c/5=23-32/9
=-9×5/9
c=-5

diff=33-(-5)=38°


tysm.#gozmit

Answer 2

Hey mate!

Here's your answer!!

$\frac{c}{5} = \frac{23 - 32}{9}$
$= - 9 \times \frac{5}{9} = - 5$
So, the difference is,

33 - (-5) = 38°

Hope it helps you!!