Question

on 5000g mass a force of 3N acts at an angle of 60 find work done in 5 second

Answer 1

W = FscosO (O represents angle b/W Force and displacement of body).

F = ma. So,

3 = 0.5 × (v - u)/t

3/0.5 = (v - 0)/5

6 × 5 = 30 = v

a = (v - u)/t

= (30 - 0)/5

= 6 m/s^2

S = ut + 1/2at^2

= 0 + 1/2 × 6 × (5)^2

= 75m

W= 3 × 75 × cos60°

= 225 × 1/2

= 112.5 J