On a 100km track, a train travels the first 30 km at a uniform speed of 30km/h. How fast
must the train travel the next 70 km so as to average 40 km/h for the entire trip?
Answers
Answered by
2
Answer:
50kmph
Explanation:
taking speed s1=30kmph
we have to calc. s2
and calculating average means
{(s1 + s2)/2} = 40kmph(given)
let me know if it was helpful..
SHUBHANGTIWARI:
but answer is 46.6666666km/hr
okay i'll check tht
well am still at 50kmph...ask others and ensure urself ..thnk yu
I got it
time taken to travel 30km=1hour
average \: speed = \frac{total \: distance}{total \: time}averagespeed=totaltimetotaldistance
average speed =40kmph
distance left=70km
let time for second time = x
\begin{lgathered}40 = \frac{30 + 70}{1 + x} \\ 40 + 40x = 100 \\ 40x = 60 \\ x = \frac{60}{40} \\ x = 1.5\end{lgathered}40=1+x30+7040+40x=10040x=60x=4060x=1.5
so speed for second time =
\begin{lgathered}70 \div 1.5 \\ = 46.66\end{lgathered}70÷1.5=46.66
so answer is 46.66km
average \: speed = \frac{total \: distance}{total \: time}averagespeed=totaltimetotaldistance
average speed =40kmph
distance left=70km
let time for second time = x
\begin{lgathered}40 = \frac{30 + 70}{1 + x} \\ 40 + 40x = 100 \\ 40x = 60 \\ x = \frac{60}{40} \\ x = 1.5\end{lgathered}40=1+x30+7040+40x=10040x=60x=4060x=1.5
so speed for second time =
\begin{lgathered}70 \div 1.5 \\ = 46.66\end{lgathered}70÷1.5=46.66
so answer is 46.66km
okay thnx
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